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In the village of don shepherd killed a baby

В донской станице овчарка загрызла младенца

In the Rostov region the dog to death killed the young girl, according to the website of the investigative Committee of Russia in the region.

According to investigators, on Friday, August 26, one of the houses in the village of Baklanovskoye Dubovskoy area 56-the summer local resident was left unattended on the territory of the household dog breed Caucasian shepherd dog.

Dog, torn from the chain and attacked the girl 2015 year of birth, who stayed with her mother in the same house. The child died at the scene.

In relation to housewife dog criminal case under article 109 of the Criminal code (“Causing death on imprudence”).

25 July in Nizhny Novgorod region, a boy of five died as a result of a dog attack. The body was discovered near the booth with a dog chain in the yard of a private house, where lived the family of the boy. Before that, mother allowed son to walk, and she stayed home with the younger children. On the child’s body was discovered multiple bites.

In Astrakhan in April, the dog dug a tunnel under the fence, escaped from the yard of a private house and killed on the street a five year old girl. The owner of the animal was sentenced to restriction of liberty and a fine in the amount of fifteen million rubles.

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